Pascal's Law Simulator — Pascal's Ball | Physlabo
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Pascal's Law: Pascal's Ball

Push the piston and water spurts from every hole of the ball at once, in all directions at the same speed. Change the force F and the piston area S: the pressure p = F/S is transmitted unchanged to every point of the liquid. The arrows inside the ball show the pressure on the walls, and the graph below the scene shows what it is made of: the added pressure F/S, the same for every hole, and the weight of the water ρgh, which grows with depth.

Mouse: left button rotates, right button or Shift pans, wheel zooms. Phone: one finger rotates, two fingers pan and zoom

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←F— force pushing the piston ↗p— water pressure on the walls of the ball

The colour of the liquid shows the pressure (scale at the bottom left). Force arrows are not to scale (∝ ∛F); the numbers are exact.

15 N
30 cm²
Holes 1.2 mm in diameter, water, ρ = 1000 kg/m³.

Pressure at a hole p = F/S + ρg(y_axis − y), jet speed v = √(2p/ρ), the drops follow the exact projectile formula. The flow Q = Σμ·A·v (μ = 0.62) moves the piston; when the water runs out, "Start" refills it.

p = F / S
added pressure — the same for every hole
Q
water flow through all holes
ptop = F/S − ρgR
pbot = F/S + ρgR
vtop = √(2p/ρ)
vbot = √(2p/ρ)
L = v·√(2H/g)
range of a sideways jet from H = 62 cm
t
water will last for

Blaise Pascal (1623–1662) was a French mathematician and physicist who built one of the first calculating machines at the age of 19. Legend has it that he fitted a narrow tube about 10 metres tall into the lid of a barrel full of water and poured just one jug of water into it — and the barrel burst. Pressure depends on the height of the liquid column, not on how much liquid there is. In 1648, at Pascal's request, his brother-in-law Florin Périer carried a mercury barometer up the Puy de Dôme mountain and showed that at the top the mercury stands lower: air pressure decreases with altitude. The unit of pressure, the pascal, is named after him.

KEY FORMULAS

Pressure

$$p = \frac{F}{S}$$

F is the force acting perpendicular to the surface, N; S is the area of the surface, m²; p is the pressure, Pa (1 Pa = 1 N/m²)

▶ Detailed Explanation

Pressure tells how much force falls on each square metre of a surface. The same force spread over a smaller area creates a larger pressure. A hand pushing a 4 cm² piston with 300 N creates an oil pressure of 300 / 0.0004 = 750,000 Pa = 750 kPa.

1 Pa is a very small pressure — roughly what a sheet of paper lying on a table exerts. That is why kilopascals and megapascals are used in practice. Atmospheric pressure at the Earth's surface is about 101 kPa.

Pascal's law

$$\Delta p_A = \Delta p_B = \Delta p = \frac{F}{S}$$

Δp is the extra pressure created by the piston (Pa); A and B are any points in the liquid

▶ Detailed Explanation

Pressure applied to a liquid or gas is transmitted unchanged to every point of the fluid and in all directions. If the piston raises the pressure beneath it by 5 kPa, then at the bottom, at the side walls and at any hole the pressure has risen by exactly 5 kPa.

A solid cannot do this: it transmits a force only along its line of action. A liquid spreads pressure in all directions because its particles slide freely past one another. That is why the jets from Pascal's ball spurt equally in all directions, and why the oil pressure in the small and big cylinders of a press is the same.

Pressure in a liquid under a piston

$$p = \frac{F}{S} + \rho g h$$

F/S is the piston pressure, the same at every point of the liquid; ρgh is the pressure of the liquid's weight, h is the depth of the point below the piston (in the ball, below the cylinder axis), m

▶ Detailed Explanation

The pressure inside a liquid has two parts. The first is the pressure created by the piston: by Pascal's law it is the same at every point. The second is the pressure of the liquid's own weight: the deeper the point, the more liquid above it and the greater the pressure.

In a Pascal's ball of radius 7.5 cm the weight of the water changes the pressure between the top and the bottom of the ball by only 2·ρgR ≈ 1.5 kPa, while a 15 N force on a 30 cm² piston adds 5 kPa. That is why the jets are almost alike, the lower ones only slightly stronger. Remove the force and only ρgh remains, so water flows only from the lower holes.

Speed of a jet from a hole

$$v = \sqrt{\frac{2p}{\rho}}, \qquad p = \rho g h \;\Rightarrow\; v = \sqrt{2gh}$$

p is the liquid pressure at the hole, Pa; ρ is the density of the liquid, kg/m³; v is the jet speed, m/s

▶ Detailed Explanation

When a volume V of water leaves through a hole, the pressure does work p·V, and it turns into the kinetic energy of the jet ρV·v²/2. Hence v = √(2p/ρ). At 5 kPa water leaves at about 3.2 m/s, at 20 kPa twice as fast, 6.3 m/s: the speed grows as the square root of the pressure.

If the pressure comes only from a water column of height h, then p = ρgh and v = √(2gh). This is Torricelli's law (1643): water leaves the hole at the speed a body would gain falling freely from the height h.

Pascal's law. Pressure applied to a liquid or gas is transmitted unchanged to every point of the fluid and in all directions. If the piston raises the pressure beneath it by 5 kPa, then at the bottom, at the side walls and at any hole the pressure has risen by exactly 5 kPa. The particles of a liquid are free to move: squeeze it from one side and they push one another in every direction until the pressure evens out. A solid cannot do this — it transmits a force only along its line of action.

Pascal's ball. It is a hollow ball with small holes, connected to a cylinder with a piston. The piston pushes the water in one direction only — along the cylinder — yet the water bursts out of the holes in every direction: up, down, sideways and even backwards, towards the piston. The jets are alike because the pressure at all the holes is almost the same. In the simulator the water is coloured by pressure, and the yellow arrows inside the ball show how it presses on the walls: arrows of equal length point every way.

Piston pressure and the weight of water. The piston pressure p = F/S depends not only on the force but also on the area: the same force on a piston half the size creates twice the pressure. On top of it comes the pressure of the water's own weight, ρgh, which grows with depth. So at a hole at height y the pressure is p = F/S + ρg(y_axis − y): a little more at the lower holes, a little less at the upper ones. With F = 15 N and S = 30 cm² the piston creates 5 kPa, while the weight of the water adds only 0.74 kPa at the bottom of the ball and takes the same away at the top. The graph shows both parts: the green rectangle F/S is the same for all holes, the blue wedge ρgh depends on height.

Jet speed. Water leaves a hole at the speed v = √(2p/ρ): the work of the pressure turns into the kinetic energy of the water. At 5 kPa this is 3.2 m/s, and a sideways jet from a height of 62 cm lands 1.1 m away. If the pressure comes only from the weight of the water, p = ρgh, the formula becomes Torricelli's law v = √(2gh) — water leaves the hole as fast as it would after falling from the height h. The drops in the simulator follow the exact projectile formula, and the outflow moves the piston: when the cylinder is empty, the jets stop.

Where Pascal's law works. It is the basis of the hydraulic press and jack, of car brakes, where pressing the pedal is transmitted by oil to all four wheels at once, and of the hydraulics of excavators and cranes. The same law explains why an inflated ball and a soap bubble are round: the gas presses equally on every part of the shell from inside.

Try it yourself. Reduce the force to zero — water then flows only from the holes below the axis of the ball, under its own weight, and not a drop leaves the upper ones. Double the force — the jets get faster and longer but stay the same in every direction. Reduce the piston area with the same force — the pressure grows although you push just as hard. Compare the speeds of the upper and lower jets in Measurements: the difference is exactly the contribution of ρgh.