Find the pressure produced by a mercury column of height $h = 76$ cm. The density of mercury is $\rho = 13600$ kg/m³, $g = 10$ m/s².
Hydrostatic pressure of a liquid column:
$$p = \rho g h = 13600 \cdot 10 \cdot 0.76 = 103\,360 \text{ Pa} \approx 1.03 \cdot 10^5 \text{ Pa}$$
$p \approx 1.03 \cdot 10^5$ Pa (103 360 Pa)