A wooden block of volume $V = 0.002$ m³ and density $\rho = 600$ kg/m³ floats in water. Find the volume of the submerged part of the block. The density of water is $\rho_{\text{water}} = 1000$ kg/m³.
For a floating body the buoyant force equals the weight of the body (the floating condition):
$$\rho_{\text{water}} g V_{\text{sub}} = \rho_{\text{body}} g V$$
$$V_{\text{sub}} = \frac{\rho_{\text{body}} V}{\rho_{\text{water}}} = \frac{600 \cdot 0.002}{1000} = 1.2 \cdot 10^{-3} \text{ m}^3$$
$$V_{\text{sub}} = 0.0012 \text{ m}^3$$
$V_{\text{sub}} = 0.0012$ m³