A capacitor of capacitance $C = 2$ uF is charged to a voltage $U = 100$ V. Find the energy stored in the capacitor.
Energy of a charged capacitor:
$$W = \frac{CU^2}{2} = \frac{2 \cdot 10^{-6} \cdot 100^2}{2} = \frac{2 \cdot 10^{-6} \cdot 10^4}{2} = 10^{-2} = 0.01 \text{ J}$$
$W = 0.01$ J