Two point charges $q_1 = 2$ uC and $q_2 = 3$ uC are placed $r = 0.1$ m apart. Find the electrostatic force between the charges. Coulomb's constant is $k = 9 \cdot 10^9$ N·m²/C².
Coulomb's law:
$$F = k \frac{q_1 q_2}{r^2} = 9 \cdot 10^9 \cdot \frac{2 \cdot 10^{-6} \cdot 3 \cdot 10^{-6}}{(0.1)^2}$$
$$F = 9 \cdot 10^9 \cdot \frac{6 \cdot 10^{-12}}{10^{-2}} = \frac{54 \cdot 10^{-3}}{10^{-2}} = 5.4 \text{ N}$$
$F = 5.4$ N