The efficiency of a heat engine is 40% and 1000 J is taken from the heater per cycle. Find the work done — Physics problems | PhysLabo
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Work of a heat engine

Easy 10 grade Molecular Physics and Thermodynamics / Thermodynamics

The efficiency of a heat engine is $\eta = 40\%$. In one cycle the engine takes a quantity of heat $Q_1 = 1000$ J from the heater. Find the work done by the engine in one cycle.

Given
  • $\eta = 40\% = 0.4$
  • $Q_1 = 1000$ J
  • $A = ?$
Hints
Hint 1 / 2
Definition of efficiency: $\eta = A/Q_1$.
Hint 2 / 2
The heat given up to the cooler is not needed for this problem.
Solution

The efficiency of a heat engine is the ratio of the work done to the heat taken in:

$$\eta = \frac{A}{Q_1} \Rightarrow A = \eta Q_1$$

$$A = 0.4 \cdot 1000 = 400 \text{ J}$$

Answer

$A = 400$ J