The amplitude of oscillation of a simple pendulum is $A = 5$ cm and the period is $T = 2$ s. Find the maximum speed of the pendulum.
The maximum speed is reached at the equilibrium position and equals $v_{\text{max}} = A\omega$, where $\omega = 2\pi/T$:
$$v_{\text{max}} = A \cdot \frac{2\pi}{T} = 0.05 \cdot \frac{2\pi}{2} = 0.05\pi \approx 0.157 \text{ m/s}$$
$v_{\text{max}} \approx 0.157$ m/s