A gas is heated isobarically (at constant pressure) from a temperature $T_1 = 300$ K to $T_2 = 450$ K. The initial volume of the gas is $V_1 = 2$ L. Find the final volume of the gas.
In an isobaric process the volume is directly proportional to the temperature (Gay-Lussac's law):
$$\frac{V_1}{T_1} = \frac{V_2}{T_2}$$
$$V_2 = V_1 \cdot \frac{T_2}{T_1} = 2 \cdot \frac{450}{300} = 2 \cdot 1.5 = 3 \text{ L}$$
$V_2 = 3$ L