A source with emf $\varepsilon = 12$ V and internal resistance $r = 1$ ohm is connected to a resistor $R = 5$ ohm (the current in the circuit is $I = 2$ A). Find the voltage across the external part of the circuit.
By Ohm's law for the external part of the circuit:
$$U = IR = 2 \cdot 5 = 10 \text{ V}$$
A second way to check — the voltage drop across the internal resistance:
$$U = \varepsilon - Ir = 12 - 2 \cdot 1 = 10 \text{ V}$$
$U = 10$ V