Two resistors of resistance $R_1 = 6$ ohm and $R_2 = 6$ ohm are connected in parallel. Find the total resistance of the combination.
For a parallel connection:
$$R = \frac{R_1 R_2}{R_1 + R_2} = \frac{6 \cdot 6}{6 + 6} = \frac{36}{12} = 3 \text{ ohm}$$
$R = 3$ ohm